Question
A sum of ₹25000 is invested in two parts, one at 8%
and the other at 10%. The total interest earned after a year is ₹2300. How much was invested at each rate?Solution
Let x be the amount invested at 8%, so 25000−x is invested at 10%. Equation for total interest: 0.08x+0.10(25000−x)=2300 Simplifying: 0.08x+2500−0.10x=2300⇒−0.02x+2500=2300 Solve for x =−0.02x=−200 ⇒ x = 10000 So: ₹10,000 was invested at 8%. ₹15,000 was invested at 10%.
B-trees and B+ trees are designed to maintain balance by adjusting the:
What is the maximum number of different Boolean functions involving n Boolean variables?
In the Entity-Relationship (ER) model, what does an entity represent?
Ternary relationship has how many participating entities?
What happens if an exception is thrown but not caught?
In a pipelined CPU design, what is the purpose of the instruction pipeline?
In a public blockchain, who can participate in the validation of transactions and creation of new blocks?
What is the decimal equivalent of the binary number 10101?
What will be the output of the code
int main(){
int array[] = {100,200,300};
cout<
}
Which circuit configuration has a single path for current flow?
Relevant for Exams:
