Question
A sum of ₹25000 is invested in two parts, one at 8%
and the other at 10%. The total interest earned after a year is ₹2300. How much was invested at each rate?Solution
Let x be the amount invested at 8%, so 25000−x is invested at 10%. Equation for total interest: 0.08x+0.10(25000−x)=2300 Simplifying: 0.08x+2500−0.10x=2300⇒−0.02x+2500=2300 Solve for x =−0.02x=−200 ⇒ x = 10000 So: ₹10,000 was invested at 8%. ₹15,000 was invested at 10%.
More Quant Miscellaneous Questions
18% of 200 - 16% of 150 = ?
(12% of 1250 + 85% of 400) x 10 = ?2
What is (0.08% of 0.008% of 8)1/9 ?
1540 ÷ 7 - 184 ÷ 8 = ?
{(81% of 800 + 28 × 4) – 27 × ?} = 11 × 20
? ÷ 62 × 12 = 264
- Evaluate: 156 ÷ 12 × 4 + 180 – 40% of 350
25% of 1000 + 10% of 150 – 22 × ? = 45
- Find the simplified value of the given expression.
672 ÷ 28 × 24 + 363 – 309 =?
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