Question
A sum of ₹25000 is invested in two parts, one at 8%
and the other at 10%. The total interest earned after a year is ₹2300. How much was invested at each rate?Solution
Let x be the amount invested at 8%, so 25000−x is invested at 10%. Equation for total interest: 0.08x+0.10(25000−x)=2300 Simplifying: 0.08x+2500−0.10x=2300⇒−0.02x+2500=2300 Solve for x =−0.02x=−200 ⇒ x = 10000 So: ₹10,000 was invested at 8%. ₹15,000 was invested at 10%.
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