Question
Quantity I: The marked price of a radio is 25% higher
than its cost price, and the shopkeeper offers a 15% discount on the marked price. The cost price of a watch is ₹480, and the shopkeeper provides a discount of x% on its marked price while earning a 25% profit. If the cost price of the radio is ₹1200, and the marked price of the watch is 56.25% higher than its cost price, what is the sum of the profit percentage on the radio and the value of x? Quantity II: 28%Solution
Answer: C From quantity I, CP of watch = 480 MP of watch = 480 * 156.25/100 = Rs.750 750 * (100 – x)/100 = 480 * 125/100 100 – x = 80 x = 20% CP of radio = 1200 MP of radio = 1200 * 125/100 = 1500 1500 * 85/100 = 1200 * (100 + y)/100 106.25 = 100 + y y = 6.25% Required = 6.25% + 20% = 26.25% Quantity I < quantity II
An increase in demand for a good will cause the equilibrium price to ______ and the equilibrium quantity to ______.
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