Question
Quantity I: The radius of a cone is twice the radius of
a sphere, and the total surface area of the cone is 704 cm². The height of the cone is equal to the length of a rectangle, and the perimeter of the rectangle (in cm) is 66 units less than the total surface area of the sphere, which is 154 cm². What is the area of the rectangle? Quantity II: The length of a cuboid is 50% greater than the side of a cube, which has a surface area of 864 cm². The ratio of the height, length, and base of the cuboid is 4:6:3. Find 25% of the volume of the cuboid. Following questions have two quantities as Quantity I and Quantity II. You have to determine the relationship between them and give an answer.Solution
Answer: C From quantity I, SA of sphere = 4 * 22/7 * r * r 154 = 4 * 22/7 * r * r Radius of the sphere = 3.5 cm Radius of the cone = 2 * 3.5 = 7 cm SA of cone = 22/7 * r * (l + r) 704 = 22/7 * 7 * (l + 7) 32 = l + 7 l = 25 cm Height of the cone = √(252 – 72) = 24 cm Length of the rectangle = 24 cm Perimeter of the rectangle = 154 – 66 = 88 cm Breadth of the rectangle = 88/2 – 24 = 20 cm Area of the rectangle = 20 * 24 = 480 cm2 From quantity II, SA of cube = 6a2 = 864 a = 12 cm Length of the cuboid = 150/100 * 12 = 18 cm Height of the cuboid = 18 * 4/6 = 12 cm Base of cuboid = 18 * 3/6 = 9 cm Volume of the cuboid = 9 * 12 * 18 = 1944 cm3 Required Answer = 1944 * 25/100 = 486 cm3 Quantity I < quantity II
What will come in the place of question mark (?) in the given expression?
? = (266 × 276) ÷ (114 × 161) × 17
Find the value: (2.4 ÷ 0.06) × (3/5) − 7.5
2/5 of 3/4 of 7/9 of 7200 = ?
What will come in the place of question mark (?) in the given expression?
4 × ? ...
- What will come in place of the question mark (?) in the following questions?
x= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
(168 ÷ 12 + 19 × 64)/(22+1) = ?
150% of 84 + ?% of 130 = 230
48 ÷ 6 × √25 + 13 × 8 = ?
2/5 of 3/4 of 7/9 of 7200 = ?