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Let the age of A = 6x years Therefore, age of B = 7x years Age of C=8 years Therefore, age of D = 36years (7x+2)/(8y–7) = 6/5… Equation(1) Sum of ages =120 13x+17y=120….. Equation(2) Solving Equation(1) & Equation(2) x=4 y=4 A=24years, D=36years Average of A and D = (24+36)/2=30years (quantity 1) Quantity 2 : Sum of q numbers = 20q So new sum = 20q + (0.5q*16) – (0.5q*20) = 18q New average = 18q/q = 18 Ans. A. Q1>Q2
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