Question
A chemist has three solutions of acid and water. The
first solution has 40 percent acid, the second has 60 percent acid, and the third has 80 percent acid. He mixes 2 liters of the first solution, 3 liters of the second solution, and 5 liters of the third solution. What is the percentage of acid in the final mixture?Solution
ATQ, Amount of acid in the first solution is 0.40 × 2 = 0.8 liters. Amount of acid in the second solution is 0.60 × 3 = 1.8 liters. Amount of acid in the third solution is 0.80 × 5 = 4 liters. Total amount of acid = 0.8 + 1.8 + 4 = 6.6 liters. Total volume of the mixture = 10 liters. Percentage of acid in the mixture = 6.6 / 10 × 100 = 66%
8, 9, 125, ?, 1331, 169Â
What value should come in the place of (?) in the following number series?
14, 18, ?, 43, 68, 104
In each of the following series, one term is missing. Find the missing term.
5, 13, 29, 61, 125, ?
96, 144, ?, 324, 486, 729, 1093.5
8, 15, 44, 175, 874, ?
12, 36, 80, 164, 328, ?
1, 6, 27, 124, ?, 3906, 27391
...251, 130, 274, ?, 301, 76Â
1056Â Â Â Â Â 264Â Â Â Â Â Â 132 Â Â Â Â Â Â 33Â Â Â Â Â Â ? Â Â Â Â Â Â 4.125
...14.8% of 7200 – 16.4% of 6200 + 15.09% of 8100 = 10% of ?
