Question
The average of a, b and c is 8 less than d. If the
average of a, b, c and d is 42, and the average of b and c is 43. then find the average of (a-6) and (d+2).Solution
ATQ, (a+b+c)/3 = d-8 a+b+c = 3d-24 a+b+c+d=42×4=168 3d-24+d = 168 4d=168+24 ∴ d=192/4 d =48 and again, b+c = 2 × 43 b+c = 86 a + b + c = 3d-24 = 144-24 =120 a = 120-86 = 34 average of (a-6) and (d+2) = ½ [(68-6) + (48+2)] = 112/2 = 5 6
More Quant Miscellaneous Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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