Question
'Ravi' can complete some work alone in 25 days. 'Shyam'
is twice as efficient as 'Mohan' and four times as efficient as 'Ravi'. If 'Ravi' and 'Mohan' start working together, then after how many days should 'Shyam' replace them so that the work gets completed in exactly 10 days?Solution
ATQ, Let the total work be 100 units. Efficiency of 'Ravi' = 100 ÷ 25 = 4 units/day Efficiency of 'Shyam' = 4 X 4 = 16 units/day Efficiency of 'Mohan' = 16 ÷ 2 = 8 units/day Let the number of days for which 'Shyam' worked alone be 'd'. So, (d X 16) + (10 - d) X (4 + 8) = 100 Or, 16d + 120 - 12d = 100 Or, 'd' = 5 So, 'Shyam' worked alone for 5 days 'Shyam' should've joined them after (10 - 5) = 5 days
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
156.76 + 14.08² + ?³ = √625.12 * 26.87
80.08% of 1250.25 + 64.02% of 1200 = 24.02 × 36.025 + ?% of 2259.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
447.79 ÷ √(√2400) + 30.94 × 6.07 – 5.08 × 21.96 = ?
Find the digit at unit place of 12349.
19.86% of 145.12 1/2 × 65.12 = ? × 2.12
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
20.05% of 150.05 – 12.15% of 99.99 × 2.02 = ?
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