Question
Speed of a boat in still water is three times the speed
of the boat in upstream. If the boat takes 30 minutes to cover 40 km in downstream, then find the speed of the boat in still water.Solution
Let speed of the boat in still water be β3xβ km/h. Speed of the boat in upstream = 3x Γ· 3 = βxβ km/h Speed of the stream = 3x β x = β2xβ km/h Speed of the boat in downstream = 3x + 2x = β5xβ km/h ATQ; (40/30) Γ 60 = 80 So, 5x = 80 Or, x = 16 So, speed of the boat in still water = 3 Γ 16 = 48 km/h
β? Γ 4 - 374 + 127 + 300 = 117
666(2/3)% of 30 - 116(2/3)% of 90 =?
23% of 8040+ 42% of 545 = ?%of 3000
35% of 840 + 162Β = ? β 25% Γ 300
What will come in the place of question mark (?) in the given expression?
?% of (112 X 3 + 164) + 75 = 2 X 140 + 35
Simplify the following expression.
(3-3 Γ 3 + 3 Γ· 3 + 3 Γ 5) Γ 2 of 5 + (2 + 2 Γ· 2 + 2 Γ 2 - 2)
What will come in the place of question mark (?) in the given expression?
(243/9) X 5 - 112 = ? Γ· (24 - 13)
What will come in the place of question mark (?) in the given expression?
20% of 10% of 900 + 84/12 = ?2
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