Question
The length of the diagonal of a rhombus is 24 cm, and
the perimeter is 80 cm. Find the area of the rhombus.Solution
Let the side of the rhombus be a. Given: Perimeter = 80 cm, so 4a = 80 a = 20 cm. Let the diagonals of the rhombus be dā = 24 cm and dā. We know that the diagonals of a rhombus bisect each other at right angles, so we can use Pythagoras' theorem: aĀ² = (dā/2)Ā² + (dā/2)Ā² 20Ā² = (24/2)Ā² + (dā/2)Ā² 400 = 12Ā² + (dā/2)Ā² 400 = 144 + (dā/2)Ā² (dā/2)Ā² = 256 dā/2 = 16, so dā = 32 cm. Area of the rhombus = 1/2 Ć dā Ć dā Area = 1/2 Ć 24 Ć 32 = 384 cmĀ². Correct option: C) 384 cmĀ²
Consider the following:
1.ArgentinaĀ
2.Mexico
3.South AfricaĀ
4.Iran
5.Malaysia
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