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    Question

    Solve the quadratic equations and determine the relation

    between x and y: Equation 1: 3x² + 6x - 9 = 0 Equation 2: 2y² - 16y + 32 = 0
    A x > y Correct Answer Incorrect Answer
    B x ≥ y Correct Answer Incorrect Answer
    C x < y Correct Answer Incorrect Answer
    D x ≤ y Correct Answer Incorrect Answer
    E No relation Correct Answer Incorrect Answer

    Solution

    From equation 1: 3x² + 6x - 9 = 0 Dividing by 3: x² + 2x - 3 = 0 Factorizing: (x + 3)(x - 1) = 0 So, x = -3 or x = 1. From equation 2: 2y² - 16y + 32 = 0 Dividing by 2: y² - 8y + 16 = 0 Factorizing: (y - 4)² = 0 So, y = 4 (double root). Comparing x and y: If x = -3 and y = 4, x < y. If x = 1 and y = 4, x < y. Thus, x < y. Answer: C

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