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Question

I. 3x² - 5x + 2 = 0

II. 6y² - 19y + 14 =0

A if x>y Correct Answer Incorrect Answer
B if x≥y Correct Answer Incorrect Answer
C if x Correct Answer Incorrect Answer
D if x≤y Correct Answer Incorrect Answer
E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

Solution

I. 3x² - 5x + 2 = 0 3x² - 3x - 2x + 2 = 0 3x (x – 1) – 2 (x – 1) = 0 (3x – 2) (x - 1) = 0 x = 1, 2/3 II. 6y² - 19y + 14 = 0 6y² - 12y - 7y + 14 = 0 6y (y – 2) – 7 (y – 2) = 0 (6y – 7) (y – 2) = 0 y = 2, 7/6 Hence, x < y

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