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Start learning 50% faster. Sign in nowLet the cost price of the article be Rs. ‘2x’
So, marked price of the article = 2x × 1.6 = Rs. ‘3.2x’
Selling price of the article = 3.2x × 0.8 = Rs. ‘2.56x’
Profit = 2.56x – 2x = Rs. ‘0.56x’
ATQ; 0.56x = 56
⇒ x = 100
Marked Price = 100 × 3.2 = Rs. 320
Selling Price = 100 × 2.56 = Rs. 256
Required difference = 320 – 256 = Rs. 64
I. 6p2 – 7p = 5p – 7p2 + 25
II. 11q2 – 63q + 90 = 0
I. 6x2 – 7x - 20 = 0
II. 3y2 - y - 14 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 135 = 0
Equation 2: y² - 26y + 153 = 0
I. x2 + 28x + 96 = 0
II. y2 + 3y - 70 = 0
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
I. 3p2 - 11p + 10 = 0
II. 42q2 + q -1 = 0
I. 7x + 8y = 36
II. 3x + 4y = 14