A vendor priced an item 45% higher than its cost price. If

I. 15/(√x)+9/(√x)=11√x

II. (√y)/4 + (5√y)/12 = 1/(√y)

I. 84x² - 167x - 55 = 0

II. 247y² + 210y + 27 = 0

I. x³ = 1728

II. y² – 15y + 56 = 0

Solve the quadratic equations and determine the relation between x and y:

Equation 1: 11x² - 93x + 88 = 0

Equation 2: 13y² + 118y + 93 = 0

I. 2x² - 9 x + 9 = 0 

II. 2y² - 7 y + 3 = 0

In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.

I. x

Find the remainder when x⁵ − 3x⁴ + 4x³ − 6x² + 8x − 3 is divided by (x − 2).

If x + 1/x = 4, find x⁵ + 1/x⁵.

I.√(3x-17)+ x=15

II.  y+  135/y=24 

Between what values of x is the expression 19x - 2x² - 35 positive?