Question
In triangle DEF, point G lies on EF such that ∠DGE =
∠DGF. If DE = 40 cm, DF = 20 cm, and EF = 24 cm, find the length of EG.Solution
ATQ, DE = 40 DF = 20 EF = 24 From before, we found: DG = √231 Use right triangle DGE: DE² = DG² + EG² 40² = (√231)² + EG² 1600 = 231 + EG² EG² = 1600 − 231 EG² = 1369 EG = 37 (Notice that EG > EF = 24 cm, so G actually lies on the extension of EF beyond F.)
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