Question
A shopkeeper purchases two mobile phones for a total of
Rs. 750. He sells the first mobile at a 20% profit and the second mobile at a 20% loss. If the selling price of both mobile phones is the same, what is the cost price of the first mobile phone?Solution
Let the cost price of 1st mobile phone be Rs. ‘x’. Then, cost price of 2nd mobile phone = Rs. (750 – x) x × 120% = (750 – x) × 80% 120x = 60000 – 80x 120x + 80x = 60000 200x = 60000 x = 300 So, cost price of 1st mobile phone = Rs. 300
The value of sec2 45˚ + 2 tan 135˚ is –
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sin 60° × cos 30° − sin 30° × cos 60°
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sin 25° × cos 65° + sin 65° × cos 25°
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Solve for 0° ≤ θ ≤ 360°:
2 sin²θ + 3 sinθ − 2 = 0
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If 2 sec 3x = 4, then the value of x: