Question
A shopkeeper purchases two mobile phones for a total of
Rs. 750. He sells the first mobile at a 20% profit and the second mobile at a 20% loss. If the selling price of both mobile phones is the same, what is the cost price of the first mobile phone?Solution
Let the cost price of 1st mobile phone be Rs. ‘x’. Then, cost price of 2nd mobile phone = Rs. (750 – x) x × 120% = (750 – x) × 80% 120x = 60000 – 80x 120x + 80x = 60000 200x = 60000 x = 300 So, cost price of 1st mobile phone = Rs. 300
√3601 × √(224) ÷ √102 = ?
16.99% of 399.99 ÷ 17.17 = ? ÷ 15.15
At a village trade fair a man buys a horse and a camel together for Rs 51,250. He sold the horse at a profit of 25 % and the camel at a loss of 20 %. If...
15.98% of 399.76 × 2.98 = ?% of 599.93Â
125.9% ÷ 9.05 x 99.98 = ? - 69.97 × √324.02 ÷ 5.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
20.22% of (61.9 × 5.01) + 69.97 =?Â
(`sqrt(224.95)` `xx` `sqrt(440.89)` ) + (`sqrt(783.82)` `xx` `sqrt(440.87)` ) = ? + 150.03% of 120.33 - 139.86% of 1249.88
...What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)<...
18.22 × 7.99 + 156.15 = ?
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