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Let the selling price of first article = 12a So, Marked price of second article = 12a + 1/12 x 12a = 13a Discount is given on second article = 12.5% So selling price of second article = 7/8 x 13a = 91a/8 Loss on first article = 14.28% So cost price of first article = 7/6 x 12a = 14a Profit on second article = 20% So cost price of second article = 5/6 x 91a/8 = 455a/48 Overall loss = (14a + 455a/48) – (12a + 91a/8) = (1127a – 1122a)/48 = 5a/48 So, 5a/48 = 120 So, a = 1152 So, sum of selling price of both articles = (12a + 91a/8) = (187 x 1152) / 8 = 26928 Hence answer is option B
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y +...
I: x2 - 33x + 242 = 0
II: y2 - 4y - 77 = 0
I. 8y2- 2y - 21 = 0
II. 2x2+ x - 6 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. 5x² + 17x + 6 = 0
II. 2y² + 11y + 12 = 0
...