Question
Ali Sold two articles, if he marked up the second
article at 8.33% above the selling price of the first article and gave a discount of 12.5% on that, then a loss of 14.28% would occurs on the first one and 20% profit on the second article. Find the sum of the selling price of both articles, if he made a total loss of Rs. 120.Solution
Let the selling price of first article = 12a So, Marked price of second article = 12a + 1/12 x 12a = 13a Discount is given on second article = 12.5% So selling price of second article = 7/8 x 13a = 91a/8 Loss on first article = 14.28% So cost price of first article = 7/6 x 12a = 14a Profit on second article = 20% So cost price of second article = 5/6 x 91a/8 = 455a/48 Overall loss = (14a + 455a/48) – (12a + 91a/8) = (1127a – 1122a)/48 = 5a/48 So, 5a/48 = 120 So, a = 1152 So, sum of selling price of both articles = (12a + 91a/8) = (187 x 1152) / 8 = 26928 Hence answer is option B
30.01 × √1023 + 196 = ? 2 – 287
70.008% of 399.98 + ?% of 399.999 = 80.105% of 599.998
? = 26.08 + 18.99 × 25.07
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40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
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4650.12 ÷ √8648.88 + √27.08 * √1727.85 = ? – 609.10 ÷ 87.07                     Â
...(439.98 ÷ 10.99) × 23.98= ? × (23.98) 2 ÷ 47.98
29.88% of 3599.90 + 5/12 of 2399.81 – 34.81% of 1200.18 = ?