Question
Ali Sold two articles, if he marked up the second
article at 8.33% above the selling price of the first article and gave a discount of 12.5% on that, then a loss of 14.28% would occurs on the first one and 20% profit on the second article. Find the sum of the selling price of both articles, if he made a total loss of Rs. 120.Solution
Let the selling price of first article = 12a So, Marked price of second article = 12a + 1/12 x 12a = 13a Discount is given on second article = 12.5% So selling price of second article = 7/8 x 13a = 91a/8 Loss on first article = 14.28% So cost price of first article = 7/6 x 12a = 14a Profit on second article = 20% So cost price of second article = 5/6 x 91a/8 = 455a/48 Overall loss = (14a + 455a/48) – (12a + 91a/8) = (1127a – 1122a)/48 = 5a/48 So, 5a/48 = 120 So, a = 1152 So, sum of selling price of both articles = (12a + 91a/8) = (187 x 1152) / 8 = 26928 Hence answer is option B
 (5/8) × 480 + (3/9) × 450 = (5/2) × ?
22 * 6 + 45% of 90 + 65% of 180 = ?
2222 ÷ 22 + 992 ÷ 16 + 650 ÷ 25 = ?
(8 x 9) ÷ 5 + ?2 = 23.4
What will come in the place of question mark (?) in the given expression?
1020 ÷ 51 × 5 + 540 of 25% - 10 = ?2Â
(25 × 12 + 30 × 8 – 22 × 10) = ?
44% of 1900 + 25% of ? = 9000
115% of 40 + 3 × 4 = ? × 11 – 8
√(?) ² = √7396 - √6889