Question
A shopkeeper purchased 80 identical articles for a total
of ₹20,000. He sold 60% of these items at a 25% profit and the remaining at a 15% loss. Calculate the overall profit or loss percentage on the entire transaction.Solution
Cost of 1 article = 20,000/80 = 250 Cost of 60% (48) articles = 250×48 = 12000 Cost of 40% (32) articles = 250×32 = 8000 Selling price of 60% articles = 125% of 12,000 = 15,000 Selling price of 40% articles = 85% of 8,000 = 6,800 Total selling price = 15,000+6,800 = 21,800 
= 9%
?3 - (77.98 ÷ 6.09 + 10.12)2 + (2.015 - 11.983)2 = 20.01 × (215.98(2/3) - √36.03)
(799.81/64) ÷ (10/799.92) × (129.84/130) = ?
...- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? + 157.99 – 101.01 = 25.01 × 5.98
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04
33.33% of 110.99 = 19.98% × 244.97 - √?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09
766/51 ÷ 387/42 × 121/13 = ?
Solve the given equation for ?. Find the approximate value.
(124.85% of 639.77 – 39.85% of 450.21) × (√224.85 ÷ √35.96) = ?
...16.01(? × 8.09 ÷ 16.09) = 3.01 of 69.69 + 14.12 of 4.01 - 100.998 of 2.19
