Question
A manufacturer produces three types of products: X, Y,
and Z. The production costs are ₹200, ₹350, and ₹500 per unit, respectively. In a month, the manufacturer produces 150 units of X, 120 units of Y, and 80 units of Z. If the company offers a 20% discount on the selling price of each product, which is set at ₹300 for X, ₹500 for Y, and ₹750 for Z, what is the total profit or loss made by the manufacturer for the month?Solution
Solution: Total production cost = (150 * 200) + (120 * 350) + (80 * 500) = ₹30,000 + ₹42,000 + ₹40,000 = ₹112,000. Selling price after discount for X = 300 - (20% of 300) = 300 - 60 = ₹240. Selling price after discount for Y = 500 - (20% of 500) = 500 - 100 = ₹400. Selling price after discount for Z = 750 - (20% of 750) = 750 - 150 = ₹600. Total selling price = (150 * 240) + (120 * 400) + (80 * 600) = 36,000 + 48,000 + 48,000 = ₹132,000. Total profit = Total selling price - Total production cost = 132,000 - 112,000 = ₹20,000 profit. Correct answer: A) ₹20,000 profit
- Identify x such that x% of 540 plus {1080 ÷ x of 9} × 6 gives 162
360 × 9 ÷ 3 + 120 + 900 ÷ 5 = ?
2350 – 4830 + 9570 + 3350 – 1720 = ?
12.5% of 384 - 16.66% of 66 = √16 + √? + 22
What will come in the place of question mark (?) in the given expression?
? = 60% of 48% of (20 × 350) + 180
What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) ÷ 15 X ? = 36 X 30
Find the simplified value of the given expression:
What is the value of 7/9-11/12+12/16-1/8?
48 ÷ 6 × √25 + 13 × 8 = ?
What will come in the place of question mark (?) in the given expression?
(308 – 154) ÷ 11 = ? ÷ 15