Question
A dealer buys three different fruits A, B & C at the
rate of Rs. 50, Rs. 40 and Rs. x per kg respectively. The quantity (by weight) of B bought by him is 25% more than A and 25% less than C. He in total gets 10% profit by selling the A and B and 20% loss by selling the C. Overall, he has no gain no loss in selling the whole quantity. What was the price of fruit C per kg? (Rs/kg)Solution
Let the quantity of A be 100y kg. Quantity of B=100y×125/100=125y Quantity of C=125y×100/75=500/3 y Quantity ratio of A, B & C respectively=12y:15y:20y Now, Total CP = 12y × (50+15y) × (40 + 20y) × x=1200y + 20xy Total SP=1200y × (110/100) + 20xy × (80/100) = 1320y+16xy ATQ, 1200y + 20xy = 1320y + 16xy x=30
864, 432, 144, ? , 7.2, 1.2
What will come in place of the question mark (?) in the following series?
2.5, 6.5, 18.5, 54.5, 162.5, 486.5, ?
161Â Â Â Â 173Â Â Â Â Â Â 191 Â Â Â Â Â Â 215Â Â Â Â Â Â 245 Â Â Â Â Â Â ?
...What will come in place of the question mark (?) in the following series?
10, 11, 15, 31, 95, ?
What will come in place of (?) question mark in the given number series.
13, 15, 18, 23, 30, ?
What will come in place of the question mark (?) in the following series?
16, 16, ?, 96, 384, 1920
14.8% of 7200 – 16.4% of 6200 + 15.09% of 8100 = 10% of ?
3, 10, 29, 66, ?
?, 32, 75, 144, 245, 384
7, 8, ?, 52, 209, 1046
