Question
A shopkeeper bought 'x - 44' kg of sugar at Rs. 60 per
kg and 44 kg of sugar at Rs. 'x' per kg and mixed them. He sold the mixture at Rs. 92.3 per kg and thus making a profit of 30%. Find the value of 'x'.Solution
Cost price of one kg of mixture = (92.3/1.30) = Rs. 71 ATQ, [{60 X (x - 44) + (44 X x)}/(x - 44 + 44)] = 71 Or, 60x - 2640 + 44x = 71x Or, 33x = 2640 So, x = 80
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)