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Let the cost price of article ‘A’ = Rs. ‘100y’ Then, selling price of the article when it is sold at a profit of 32% = 1.32 × 100y = Rs. ‘132y’ And, selling price of the article when it is sold at a loss of 40% = 0.60 × 100y = Rs. ‘60y’ According to the question, 132y – 60y = 810 Or, y = (810/72) Or, y = 11.25 So, cost price of article ‘A’ = 100 × 11.25 = Rs. 1125 Therefore, cost price of article ‘B’ = 1125 + 80 = Rs. 1205
13% of 200 + 56 ÷ 4 = 8% of ?
√1764 + 35 × 8 + 39 = ?2
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
(√2704 x 55)/(245 + 120) =?
√1369 + √1024 + √841 =(?)2 − 46
60 = (? x 10 + 250)/5
263 + 1152 - ? + 577 = 1333
2197 1/3 + 30% of 1800 = ?× 343 1/3
42 + 52% of 300 - ?% of 200 = 88