Question
Two students appeared in an exam and one secured 16
marks more than the other. If marks of student who got more marks is 54% of the sum of the marks of both of them, then find the marks obtained by them.Solution
Let total marks obtained by both of them is x and y respectively. x – y = 16 And, x = 0.53 × (x + y) x = 0.53 × (16 + y + y) x = 0.53 × (16 + 2y) x = 8.64 + 1.08y 16 + y = 8.64 + 1.08y 0.08y = 7.36 y = 92 x = 92 + 16 = 108
More Profit and loss Questions
81% of 2300 – 34% of 550 = ?
(22 + √3364)/(? + 4) = 10
375% of 320 - 80% of 40 ÷ √256 = ?
(21% of 360) ÷ 0.8 =?
25% of 1000 + 10% of 150 – 22 × ? = 45
(20% of 15% of 600 – 6) × 5 + 84 = ?2
? ÷ [35% of 379 - 34(4/5)] = 0.4
What will come in the place of question mark (?) in the given expression?
? = 12.5% of 25% of 20% of 1280 + 1248
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 ×9.05 =?
√256 * 4 – 30% of 190 + ? = 110% of 220
