Question
'A' purchased an article and sold it to 'B' at 10%
profit. 'B' marked it up by 15% above the price at which 'A' has purchased it and then sold it after giving a discount of Rs. 496. If 'B' suffered a loss of 18% in the transaction, then find the cost price of the article for 'A'.Solution
Let the cost price of the article for A be Rs. x Therefore, cost price of the article for B = Rs. 1.1x Marked price of the article = Rs. 1.15x Selling price of the article for B = 0.82 × 1.1x = Rs. 0.902x According to the question, 1.15x – 0.902x = 496 Or, x = 496/0.248 = 2000 Therefore, cost price of the article for A = Rs. 2000
What will come in place of a?
(6)1.2 × (216 )2.7 × (36)2.7 = 6a
Simplify:
(0.72 ÷ 0.12) − (3/5 × 2.5) + 7/8
(161051)Â -3/5Â = ?
If √7 × √35 = x√5, then find the value of x
Simplify: (16)(3/4) × (8)(2/3)
The value of ‘x’ in the given below equation is.
0.5 Ì… + 0.7 Ì… + 0.9 Ì… + 0.3 Ì… = x
Find the value of 56 × 59 ÷ 514 = ?
(0.09)Â -1.5Â = ?
- Find the value of (256 x 4096)/(400 x 125 x 64)Â = ?
3√4913+ 3√4.913 + 3√0.004913 = ?