Question
The ratio of the cost price and marked price of an
article is 3:7, respectively. The article is sold after giving a discount of Rs. 800 such that there is a profit of 50%. Find the amount by which the article is marked up above its cost price. ÂSolution
Let the cost price and marked price of the article be Rs. 3x and Rs. 7x, respectively Therefore, selling price of the article = 1.5 × 3x = Rs. 4.5x According to the question, 7x – 4.5x = 800 Or, x = 800/2.5 = 320 Therefore, amount by which article is marked up above its cost price = 7x – 3x = 4x = Rs. 1280
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 50x + 600 = 0
Equation 2: y² - 51y + 630 = 0
I. 10x² - 11x + 3 = 0
II. 42y² - 23y – 10 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
- Determine the remainder when equation 4p³- 5p² + 2p + 1 is divided by (4p - 3).
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 13x² - 60x + 47 = 0
Equation 2: 17y² - 80y + 63 = 0
Equation 1: x² - 250x + 15625 = 0
Equation 2: y² - 240y + 14400 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
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