Question
A trader marked an article 50% above its cost price and
sold it after allowing a discount of 20%. If the transaction resulted in a profit of Rs. 200, then find the cost price of the articleSolution
Let the cost price of the article be Rs. ‘x’ Marked price of the article = x × 1.50 = Rs. ‘1.5x’ Selling price of the article = 1.5x × 0.8 = Rs. ‘1.2x’ Profit = 1.2x – x = Rs. ‘0.2x’ ATQ; 0.02x = 200 So, x = 1000 Therefore, cost price of the article is Rs. 1000.
Speed of a boat in still water to speed of boat in upstream is 7: 6. If the boat can travel 320 km in downstream in 4 hours, then find the time taken by...
A boat can travel 36 km downstream in 45 min. The ratio of the speed of the boat in still water to the speed of the stream is 5: 1. How much time will t...
A submarine can travel a certain distance downstream in 4 hours and the same distance upstream in 8 hours. If the submarine's speed in still water is 12...
Ratio of downstream and upstream speed of a boat is 5:2. If the speed of stream is 3 km/h, find the distance travelled by boat in downstream in 2 hours.
A boat can cover 200 km in downstream in 10 hours and 150 km in upstream in 15 hours. Find the distance travelled by the boat in still water in 5 hours.
A boat's speed in calm water exceeds the speed of the current by 12 km/hr. Given that the current's speed is 1.25x km/hr and the boat takes 5 hours to t...
Speed of a boat in still water to speed of boat in upstream is 10:7. If the boat can travel 390 km in downstream in 5 hours, then find the time taken by...
A kayaker covers 64 km upstream and 96 km downstream in 8 hours and 6 hours, respectively. Find the time taken by the same kayaker to cover 140 km in st...
The speed of the boat in still water is 12 km/hr and the speed of the stream is 9 km/hr. A boat goes 105 km downstream with its usual speed but at the t...
Two boats X and Y start towards each other from two places, 155 km apart. Speed of the boat X and Y in still water are 14 km/hr and 17 km/hr respectivel...
