Question
A trader marked an article 70% above its cost price and
sold it after allowing a discount of 40%. If the transaction resulted in a profit of Rs. 24, then find the cost price of the articleSolution
Let the cost price of the article be Rs. ‘x’ Marked price of the article = x × 1.7 = Rs. ‘1.7x’ Selling price of the article = 1.7x × 0.6 = Rs. ‘1.02x’ Profit = 1.02x – x = Rs. ‘0.02x’ ATQ; 0.02x = 24 So, x = 1200 Therefore, cost price of the article is Rs. 1200.
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 375 = 0
Equation 2: y² - 36y + 324 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. 2x2 – 19x + 45 = 0
II. y2 – 14y + 48 = 0
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I. 2x2 – 5x – 63 = 0
II. 2y2 – 7y – 72 = 0
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
I. 6p2 – 7p = 5p – 7p2 + 25
II. 11q2 – 63q + 90 = 0
I. 12x2 + 22x + 8 = 0
II. 4y2 - y − 3 = 0
