Start learning 50% faster. Sign in now
Let the cost price of the article be Rs. ‘x’ Marked price of the article = x × 1.7 = Rs. ‘1.7x’ Selling price of the article = 1.7x × 0.6 = Rs. ‘1.02x’ Profit = 1.02x – x = Rs. ‘0.02x’ ATQ; 0.02x = 24 So, x = 1200 Therefore, cost price of the article is Rs. 1200.
If (3 × 144 – 252 ÷ 14) ÷ 18 = √1024 – x, then find the value of ‘x’.
(200 + 50% of 120) ÷ (9 × 2) = ?
(560 ÷ 32) × (720 ÷ 48) = ?
If √3n 729, then the value of n is equal to:
(〖(0.4)〗^(1/3) × 〖(1/64)〗^(1/4) × 〖16〗^(1/6) × 〖(0.256)〗^(2/3))/(〖(0.16)〗^(2/3) × 4^(-1/2) ×〖1024〗^(-1/4) ) = ?
18/2 of 3/9 of 2/6 of 69690= ?
√10000 x √8100 - (50)² = √(?) + (80)²
40.5 ÷ [4/5 of (32 + 18) - 29/2] = ? ÷ 102
416 ÷ 8 + 132 – 25% of 420 = ?