Question
A, B and C enter into a partnership, A invest 6X +
15000, B invest 3X + 1000 and C invest X + 8000 for one year if B share is 4000 from total profit of 16000 then find the difference between investment of A and C.Solution
According to question, (3x + 1000)/(6x + 15000 + 3x + 1000 + x + 8000) = 4000/16000 X = 10000 Required difference → 6x + 15000 - x - 8000 = 57000
I). p2 = 81
II). q2 - 9q + 14 = 0
I. 2y2Â + 31y + 99 = 0
II. 4x2 + 8x – 45 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. x=  √(20+ √(20+ √(20+ √(20…………….∞)) ) )Â
II. y= √(5√(5√(5√(5……….∞)) ) )Â
...I. 2x2 – 25x + 33 = 0
II. 3y2 + 40y + 48 = 0
I. 6x² - 49x + 99 = 0
II. 5y² + 17y + 14 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21x² - 122x + 160 = 0
Equation 2: 23y² - 159y + ...
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 33x² - 186x + 240 = 0
Equation 2: 35y² - 200y + ...
