Question
A costs twice as much as B. A is sold at a loss of 15%
and B is sold at 8/5th of its price. If selling price of A is Rs. 500 more than selling price of B, what is the cost price of A?Solution
Let the CP of B be 100x. CP of A = 2 × 100x = 200x Now SP of A = 85% of 200x = 170x And SP of B = 100x × 8/5 = 160x According to question, => 170x – 160x = 500 => x = 50 CP of A = 200x = 200 × 50 = Rs. 10000
Find the number of zeroes in 18 × 125 × 20 × 32.
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
- If (x - y) = 5, then find the value of (x³ - y³ - 15xy).
Find ‘x’ if (x³+3x)/(3x²+1) = 189/61
If, 3x + 2y = 15, and 2xy = 12, and 3x > 2y, then find the value of 27x³ – 8y³.
x = 7 - 4√3 then the value of x³+1/x³ is equal to?
Suppose xy = -15 and (x² + y²) = 34, then determine the value of (x – y).
If p = 32 - q - r and pq + r(q + p) = 255, then find the value of (p² + q² + r²).
If (a – 8) 2  + (b + 2) 2 + (c – 3) 2  = 0, then find the value √(a +b + c).
...
