Question
A loss of 15% is made by selling an article. Had it been
sold for Rs.75 more, there would have been a profit of 10%. What would be the selling price of the article if it is sold at 20% profit?Solution
CP of an article = 75 × 100/[10 – (-15)] = Rs.300 SP at 20% profit = (120/100) × 300 = Rs.360
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x2 + 6√7x - 315 = 0    Â
E...
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 30x + 221 = 0
Equation 2: y² - 28y + 189 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. p2 - 19p + 88 = 0  Â
II. q2Â - 48q + 576 = 0
I. 2x2 + 13x + 21 = 0
II. 3y2 + 34y + 63 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
What will be the product of smaller roots of both equations.Â
(i) x² – 3x – 40 = 0
(ii) y² + 11y + 30 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
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