Let S be the sample space. Then, n(S) = 52C 2 = `(52 xx 51)/(2 xx 1)` = 1326 Let E = event of getting 1 ace and 1 jack. n(E) = number of ways of choosing 1 ace out of 4 and 1 jack out of 4 = 4C1`xx` 4C1= `4 xx 4` = 16 `:.` P (E) = `(n(E))/(n(S))` = `16/1326` = `8/663`
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