Question
Two cards are drawn from a pack of 52 cards. The
probability that 1 is Ace and 1 is Jack is?Solution
Let S be the sample space. Then, n(S) = 52C 2 = `(52 xx 51)/(2 xx 1)` = 1326 Let E = event of getting 1 ace and 1 jack. n(E) = number of ways of choosing 1 ace out of 4 and 1 jack out of 4 = 4C1 `xx` 4C1 = `4 xx 4` = 16 `:.` P (E) = `(n(E))/(n(S))` = `16/1326` = `8/663`
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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