A box contains 6 red, 4 blue, 2 green and 4 yellow pens. Two pens are picked at random, what is the probability that one is blue and one is yellow?
Total number of pens = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 2 pens out of 16 = ¹⁶C2 = (16 × 15 )/( 2 × 1) = 120 Let E= event of drawing two pens so that one is blue and one is yellow n(E) = ⁴C1× ⁴C1= 4 × 4= 16 ∴ P (E) = (n(E))/(n(S)) = 16/120 = 2/15
