Question
A box contains 6 red, 4 blue, 2 green and 4 yellow pens.
Two pens are picked at random, what is the probability that one is blue and one is yellow?Solution
Total number of pens = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 2 pens out of 16 = ¹⁶C2 = (16 × 15 )/( 2 × 1) = 120 Let E= event of drawing two pens so that one is blue and one is yellow n(E) = ⁴C1 × ⁴C1= 4 × 4= 16 ∴ P (E) = (n(E))/(n(S)) = 16/120 = 2/15
√ (12+√ (12+√ (12+ ⋯ ∞ ))
[4(1/3) + 4(1/4)] × 24 – 62 = ?2
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43
What will come in place of (?) in the given expression.
(18 + 24 ÷ 6) × 2 - 5 = ?(117 + 93 - 10) ÷ 40 = ? - 12 X 2
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
What will come in the place of question mark (?) in the given expression?
(24 2 – 16 2 ) + 75% of 40% of 480 = ?
If 1560 ÷ 30 + 2025 ÷ 45 - z + 33 × 7 = 1848 ÷ 24 × 234 ÷ 39, then the value of z is:
4.7 × 3.5 + 4.2 × 4.5 = 22.5 × 3.5 - ?
2/5 of 3/4 of 7/9 of 14400 = ?
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