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    Question

    A box has 5 red and 3 blue balls. Two balls drawn

    without replacement. Probability of at least one blue?
    A 11/13 Correct Answer Incorrect Answer
    B 9/14 Correct Answer Incorrect Answer
    C 12/13 Correct Answer Incorrect Answer
    D 12/17 Correct Answer Incorrect Answer

    Solution

    ATQ,

    P(no blue) = C5,2 / C8,2 = 10/28 = 5/14 So P(at least one blue) = 1 тАУ 5/14 = 9/14

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