Question
A box has 5 red and 3 blue balls. Two balls drawn
without replacement. Probability of at least one blue?Solution
ATQ,
P(no blue) = C5,2 / C8,2 = 10/28 = 5/14 So P(at least one blue) = 1 – 5/14 = 9/14
More Probability Questions
5.5 × 3.2 × 2.3 = ?
What value will come in place of (?) question mark in the given expression.
17 × 15 – 48 ÷ 4 + 9² = ?
Find the value of.
( ∛ ∛ 343 )3 × ( ∛ ∛216 )3
(3984 ÷ 24) x (5862 ÷ 40) = ?
5555 ÷ 11 ÷ 5 = 100 + ?
18 * 9 + 25% of 120 + 50% of 200 = ?
Simplify the following expressions and choose the correct option.
18² + (27 ÷ 3) × 11 − 250 = ?
What will come in the place of question mark (?) in the given expression?
(20% of 820 – 56 + 11 × 8) 1/2 = ? – 62
Simplify the following expressions and choose the correct option.
√2116 + 152 ÷ 9 - 33
