Question
A bag contains βx + 2β red, βx + 4β blue and
β2x β 2β green Gloss papers. Two papers are randomly drawn from the bag, so the probability that a blue paper and a green paper are drawn is 4/15. Determine the total number of papers in the bag.Solution
According to question: x+4C1 Γ 2x-2C1/Β 4x+4C2 = 4/15 2(x + 4) Γ (2x β 2)/{(4x + 4) Γ (4x + 3)} = 4/15 (x + 4)(x β 1)/{(x + 1)(4x + 3) = 4/15 15x2 + 45x β 60 = 16x2 + 28x + 12 x2 β 17x + 72 = 0 x2 β 9x β 8x + 72 = 0 x(x β 9) β 8(x β 9) = 0 (x β 9)(x β 8) = 0 x = 8, 9 So the total number of papers in the bag = either 4 Γ 8 + 4 = 36 or 4 Γ 9 + 4 = 40
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