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    Question

    In a silver box there are 8 green, 3 red, and 4 blue

    pens while in a gold box there are 6 green, 7 red, and 3 blue pens. One pen is drawn at random from the combined pens of both boxes. Find the probability that it is a red pen from the gold box.
    A 7/31 Correct Answer Incorrect Answer
    B 7/32 Correct Answer Incorrect Answer
    C 3/31 Correct Answer Incorrect Answer
    D 1/4 Correct Answer Incorrect Answer
    E 7/30 Correct Answer Incorrect Answer

    Solution

    Total pens in silver box = 8 + 3 + 4 = 15
    Total pens in gold box = 6 + 7 + 3 = 16
    Total pens combined = 15 + 16 = 31
    Probability pen is from gold box = 16/31
    Probability pen is red given gold box = 7/16
    Required probability = (16/31) × (7/16) = 7/31

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