Question
A number is randomly chosen from 1 to 100(both
inclusive). What is the probability that it is divisible by 2, 3 or 5?Solution
Total numbers divisible by 2 = 100/2 = 50
Total numbers divisible by 3 = 100/3 = 33
Total numbers divisible by 5 = 100/5 = 20
Numbers that are multiples of 2 and 3, 3 and 5, 2 and 5 would have been added twice. So we need to subtract it.
Total numbers divisible by 2 and 3 = 100/6 = 16
Total numbers divisible by 3 and 5 = 100/15 = 6
Total numbers divisible by 2 and 5 = 100/10 = 10
We now need to add the number divisible by 2,3, and 5
LCM = 2 x 3 x 5 = 30
Total numbers divisible by 30 = 100/30 = 3
So numbers divisible by 2,3 or 5 = 50 + 33 + 20 - (16 + 6 + 10) + 3 = 103 - 32 + 3 = 74
Required probability = 74/100 = 37/50
Determine the simplified value of the given mathematical expression.
((8)0- (0.1)-1)/( (6/16)-1 ×(3/2)3+ ((-2)/6)-1) = ?/2
(22% of 1500 + 15% of 2200) = ? x 11
Simplify the given expression:
[(2.3)3 + (15.9) ³ + (3.7) ³ – 3 × 2.3 × 15.9 x 3.7)] / [(2.3) ² + (15.9) ² + (3.7) ² – 2.3 ...
What is the place value of 6 in 367892141?
(21 × 51 + 81)/(9 × 14 - 30) = ?
10% of 100 + 14 = ?% of 120
24% of 400 × 16% of ? = 384
- What will come in place of the question mark (?) in the following questions?
25% of 360+40=?