Question
A number is randomly chosen from 1 to 100(both
inclusive). What is the probability that it is divisible by 2, 3 or 5?Solution
Total numbers divisible by 2 = 100/2 = 50
Total numbers divisible by 3 = 100/3 = 33
Total numbers divisible by 5 = 100/5 = 20
Numbers that are multiples of 2 and 3, 3 and 5, 2 and 5 would have been added twice. So we need to subtract it.
Total numbers divisible by 2 and 3 = 100/6 = 16
Total numbers divisible by 3 and 5 = 100/15 = 6
Total numbers divisible by 2 and 5 = 100/10 = 10
We now need to add the number divisible by 2,3, and 5
LCM = 2 x 3 x 5 = 30
Total numbers divisible by 30 = 100/30 = 3
So numbers divisible by 2,3 or 5 = 50 + 33 + 20 - (16 + 6 + 10) + 3 = 103 - 32 + 3 = 74
Required probability = 74/100 = 37/50
564.932 + 849.029 β 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of βΉ60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to βΉ75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 Γ· 40.48 Γ 10.12 = ? Γ 2.16
(124.901) Γ (11.93) + 219.95 = ? + 114.891 Γ 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...