Question
Bag A contains 3 red, 4 black, 8 blue and 5 yellow balls.
Bag B contains 5 red, 2 black, 4 blue and 3 yellow balls. Find the probability of drawing 2 blue balls and 1 red ball from either of the bag.Solution
Probability of selecting one bag = 1/2
Probability of drawing 2 blue balls and 1 red ball from bag A = ( 8 c 2  x 3 c 1 )/ 20 c 3 = (28 x 3)/1140 = 7/95
Probability of drawing 2 blue balls and 1 red ball from bag B = ( 4 c 2  x 5 c 1 )/ 14 c 3 = (6 x 5)/364 = 15/182
Required probability = ½ x (7/95 + 15/182)
= 7/190 + 15/364 = (1274 + 1425)/34580 = 2699/34580
More Probability Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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