Question
Three Marbles and three balls are kept in a box. If two
items are chosen at random, Find the probability that one is marble and another one is ball?Solution
Total probability = 6C2 = 15 Probability that one is marble and another one is ball = 3C1 × 3C1 = 9 probability = 9/15 = 3/5
319.995 × 15.98 ÷ 4.002 - ? × 7.95 = 1679.89 ÷ 2.005
564.932 + 849.029 – 425.08 = 612.095 + ?
`root(3)(725.87)` `-:` `sqrt(81.033)` Â + 49.88% of 809.77 = ? - (14.78Â `xx` Â 52.2)
9.8 × 77.9 ÷ (2.3)2 = ?
What value should come in place of question mark (?) in the following question. (You need not to calcualte the exact value)
?/647 = 226/ ?
499.99 + 1999 ÷ 39.99 × 50.01 = ?
79.99% of (84.89 × 5.99) - (3.89)2 × 21.87 = ?
(112 × 4) ÷ 16 + 484 = (?)3
72.8% of (215.69 + 189.38) - 5.97² + (3.01 of 7.8) = ? of (64.02 - 38.95)