Question
In a box there are 6 red, 12 blue, and 18 yellow cards.
One card is picked up randomly. What is the probability that it is neither red nor yellow?Solution
Total number of cards = 6 + 12 + 18 = 36 Let E= event that the card drawn is neither red nor yellow = event that the card drawn is blue. ∴ n(E) =12 ∴ P(E) = 12/36 = 1/3
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Two numbers P and Q are in the respective ratio 7: 9 and their sum is 80. Then, P is equal to:
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