Question
In a circle, two chords MN and PQ intersect at O. If MO
= 9 cm, ON = 5 cm and OQ = 6 cm, then the value of OP (in cm) is:Solution
Given: MO = 9 cm ON = 5 cm OQ = 6 cm We use the chord-chord product theorem: MO × ON = PO × OQ Substituting the known values: 9 × 5 = OP × 6 45 = 6 × OP OP = 45/6 =7.5 cm
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