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    Question

    In a circle, two chords MN and PQ intersect at O. If MO

    = 9 cm, ON = 5 cm and OQ = 6 cm, then the value of OP (in cm) is:
    A 7.5 Correct Answer Incorrect Answer
    B 6.5 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 7 Correct Answer Incorrect Answer

    Solution

    Given: MO = 9 cm ON = 5 cm OQ = 6 cm We use the chord-chord product theorem: MO × ON = PO × OQ Substituting the known values: 9 × 5 = OP × 6 45 = 6 × OP OP = 45/6 ​=7.5 cm

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