Question
A policeman noticed a thief at a distance of 500 metres.
The policeman started running and the thief also started running at the same time. The thief is running at a speed of 15 km/h. It took 15 minutes for the policeman to catch the thief. Find the speed of the policeman (in km/h).Solution
Let the speed of the policeman be x km/h. The thief runs at 15 km/h and was 500 meters (0.5 km) ahead. Time taken to catch the thief is 15 minutes = 0.25 hours. Relative speed = x − 15 km/h Distance = 0.5 km Time = 0.25 hours Using the formula: Distance = Speed ×Time 0.5 =(x − 15) × 0.25 0.5/0.25 = x − 15 2 = x − 15 x = 17
(500 × 6 ÷ 10) - (√256 + 8) = ?
22% of 400 + √ ? = 34% of 800 - 25% of 400
(2/5)(32% of 4500 – 440) = ? × 8
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
What will come in the place of question mark (?) in the given expression?
96 ÷ (9 - 6.6) + 17.5 X 6 = ? ÷ 8
13 X ? = 85 X 4 + √81 + 2
45% of 360 - 160 + ? = √324
((67)32 × (67)-18 / ? = (67)⁸
4567.89 - 567.89 - 678.89 = ?
82.3 × 644.7 × 723.4 × 815.85 = 72?