Question
Simplify: 13 β [7 β (4 + 7) β {7 β (7 β
4 + 7)} + 14]Solution
13 β [7 β (4 + 7) β {7 β (7 β 4 + 7)} + 14] = 13 β [7 β 11 β {7 β (7 β 4 + 7)} + 14]Β Β = 13 β [7 β 11 β {7 β (3 + 7)} + 14]Β Β = 13 β [7 β 11 β {7 β 10} + 14]Β Β = 13 β [7 β 11 β {β3} + 14]Β Β = 13 β [7 β 11 + 3 + 14]Β Β = 13 β [(7 β 11) + 3 + 14]Β Β = 13 β [(β4) + 3 + 14]Β Β = 13 β [(β4 + 3) + 14]Β Β = 13 β [(β1) + 14]Β Β = 13 β [13]Β = 13 β 13Β Β = 0
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