Question
Let C be a circle with centre O and P be an external
point to C. Let PA and PB be two tangents to C with A and B being the points of tangency, respectively. If PA and PB are inclined to each other at an angle of 60°, then find∠POA.Solution
Let C be a circle with center O and P be an external point. PA and PB are tangents from P to the circle, with A and B being the points of tangency. The angle between the tangents PA & PB is given as 60°. The angle between the radii OA and OB (subtended by the tangents at the center) is 2 x the angle between the tangents, So, angle AOB = 2 x 60° = 120°. The angle POA (half of angle AOB) is 60°, as the tangents subtend equal angles at the center.
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