Question
Two circles of radius 13 cm and 15 cm intersect each
other at points A and B. If the length of the common chord is 12 cm, then what is the distance between their centres?Solution
Let O and R be the center of the circle and PQ be the length of the common chord. OP = 15, RP = 13 PS = 1/2 PQ (as perpendicular from the center of the circle to a chord bisects the chord) PS = 1/2 Γ 12 PS = 6 By applying Pythagoras theorem in PSO: OS2 = OP2-PS2 = 152 β 62 = 225-36 = 189 Β OS = β189 Β By applying Pythagoras' theorem in PSO': RSΒ² = RP2-PS2 = 132 - 62 = 169-36 = 133 RS = β133 OR = OS + RS = β189 + β133 The distance between their centers = β189 + β133
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