Question
A person travels from the hostel to the college with a
speed of 15 kmph from the bicycle and arrives at a delay of 2.5 minutes. If he runs a bike with a speed of 20 kmph then it reaches 2.5 minutes. Describe the distance between hostel and college. (In km)Solution
As we know, Speed = Distance/time Let us consider the actual time of journey be t hrs, As we know, the distance is same According to the question 15 (t + 2.5/60) = 20 (t-2.5/60) 3 (t + 1/24) = 4 (t-1/24) 3t+ 3/24 = 4t-4/24 Β 4t-3t=3/24 + 4/24 β t = 7/24 Distance = speed Γ time Distance = 15 (7/24 + 2.5/60) = 15 (7/24 + 1/24) = 15 Γ 8/24 = 5 km The distance between the hostel and the college is 5 km.
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