Question
The diameter of a sphere is increased by 30%. What is
the percentage increase in its volume?Solution
Let the initial radius be r Initial V = 4/3(ĻĪ¹Ā³) Changed radius = 1.30r Changed V = 4/3[Ļ (1.30r)3] = 2.197 Ć 4/3(ĻĪ¹Ā³) Percent increase in its volume = [{2.197 Ć 4/3(ĻrĀ³) - 4/3(ĻrĀ³)}/4/3(ĻrĀ³)] Ć 100 Ā Percent increase in its volume = 119.7%
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