Question
The diameter of a sphere is increased by 30%. What is
the percentage increase in its volume?Solution
Let the initial radius be r Initial V = 4/3(πι³) Changed radius = 1.30r Changed V = 4/3[π (1.30r)3] = 2.197 × 4/3(πι³) Percent increase in its volume = [{2.197 × 4/3(πr³) - 4/3(πr³)}/4/3(πr³)] × 100  Percent increase in its volume = 119.7%
Pusa Deepali is a variety of:
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