Question
The diameter of a sphere is increased by 30%. What is
the percentage increase in its volume?Solution
Let the initial radius be r Initial V = 4/3(πι³) Changed radius = 1.30r Changed V = 4/3[π (1.30r)3] = 2.197 × 4/3(πι³) Percent increase in its volume = [{2.197 × 4/3(πr³) - 4/3(πr³)}/4/3(πr³)] × 100  Percent increase in its volume = 119.7%
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`1804/898-:99/699xx749/751=?`
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
Direction: Please solve the following expression and choose the closest option
`(13.022)^(2)+ (42.93)^(2)-(53.125)^(2)+(192.33xx14.88)=?- (88.44)^(2)- (42.03 xx 23.12)`
√49 + 6.66% of 1725 + 22² = ?² - √361Â
What approximate value will replace the question mark (?) in the following?
? =...
? = 49.97% of 38.09% of 1998.95
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
