Question
A bag contains 600 coins of ₹1 denomination and 1200
coins of ₹2 denomination. If 10% of ₹1 coins and 15% of ₹2 coins are removed, the percentage of money removed from the bag isSolution
ATQ, Let's calculate the percentage of money removed from the bag after 10% of ₹1 coins and 15% of ₹2 coins are removed. Step 1: Calculate the total value of ₹1 coins and ₹2 coins in the bag before removal. Total value of ₹1 coins = 600 coins × ₹1/coin = ₹600 Total value of ₹2 coins = 1200 coins × ₹2/coin = ₹2400 Step 2: Calculate the value of ₹1 coins and ₹2 coins removed. Value of ₹1 coins removed = 10% of ₹1 coins = 0.10 × ₹600 = ₹60 Value of ₹2 coins removed = 15% of ₹2 coins = 0.15 × ₹2400 = ₹360 Step 3: Calculate the total value of coins removed. Total value of coins removed = Value of ₹1 coins removed + Value of ₹2 coins removed Total value of coins removed = ₹60 + ₹360 = ₹420 Step 4: Calculate the percentage of money removed. Percentage of money removed = (Total value of coins removed / Total value of coins before removal) * 100% Percentage of money removed = (₹420 / ₹3000) × 100% Percentage of money removed ≈ 14% So, approximately 14% of the money has been removed from the bag.
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. 6y2 - 17y + 12 = 0
II. 15x2 - 38x + 24 = 0
I. 4x2 – 53x – 105 = 0
II. 3y2 – 25y + 48 = 0
I. 9/(4 )p + 7/8p = 21/12
II. 7/5p = 9/10q + 1/4
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
Quantity I: A vessel contains a mixture of milk and water in the ratio of 7 : 5. If 9 litre of mixture is sold and replaced by same amount of water then...
