Question
There are five boxes in a cargo hold. The weight of the
first box is 200 kg and the weight of the second box is 20% higher than the weight of the third box, whose weight is 25% higher than the first box's weight. The fourth box at 350 kg is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and the four lightest boxes:Solution
Let the weight of five boxes be W1, W2, W3, W4 and W5 respectively. ATQ: W1 = 200 kg W3 = 125/100 × 200 = 250 kg W2 = 120/100 × 250 = 300 kg W4 = 350 W5 = 350 × 100/70 = 500 kg Now, Avereage weight of 4 heaviest boxes = (500 + 350 + 300 + 250)/4 = 350 kg Avereage weight of 4 lightest boxes = (200 + 250+ 300 + 350)/4 = 275 kg Required difference = 350 - 275 = 75 kg
Statements: Z % Y; X # W; U % V; W & V; Y @ X
Conclusions:Â Â Â Â Â
I. U @ X Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
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Conclusion:
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