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    Question

    What is the greatest four digit number which when

    divided by 6, 9, 12, 15 and 18 leaves remainder 1 in each case?
    A 9901 Correct Answer Incorrect Answer
    B 9902 Correct Answer Incorrect Answer
    C 9904 Correct Answer Incorrect Answer
    D 9908 Correct Answer Incorrect Answer

    Solution

    L.C.M. of 6, 9, 12, 15 and 18 = 180 To find the largest 4 digit number which, when divided by 6, 9, 12, 15 and 18, leaves remainder 1, we have to divide the 9999 by 180 and add 1 after subtracting the remainder from 9999. When we divide the 9999 by 180, the remainder is 99. Required number = 9999 – 99 + 1 = 9901

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