Question
What is the greatest four digit number which when
divided by 6, 9, 12, 15 and 18 leaves remainder 1 in each case?Solution
L.C.M. of 6, 9, 12, 15 and 18 = 180 To find the largest 4 digit number which, when divided by 6, 9, 12, 15 and 18, leaves remainder 1, we have to divide the 9999 by 180 and add 1 after subtracting the remainder from 9999. When we divide the 9999 by 180, the remainder is 99. Required number = 9999 – 99 + 1 = 9901
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