Question

    A 60-litre mixture of acid and water contains 33(1/2%) 

    acid. How much water (in litres) must be added to get a mixture having 25% acid?
    A 15 Correct Answer Incorrect Answer
    B 210 Correct Answer Incorrect Answer
    C 20 Correct Answer Incorrect Answer
    D 30 Correct Answer Incorrect Answer

    Solution

    In 60 liters solution 34 liter acid and 66 liter water In 60 liters solution, water is  (66/100) × 60 = 6.6 x 6 = 39.6 or ~ 40 liter On adding x liters of water [(40 + x)/(60 + x)] x 100 = 75 On dividing 100 and 75 we get 4 and 3 value then [(40 + x)/(60 + x)] x 4 = 3 (160 + 4x)/(60 + x ) = 3 160 + 4x = (60 + x) x 3 160 + 4x = 180 + 3x 4x - 3x = 180 - 160 x = 20 Liter

    Practice Next
    More Previous year papers Questions
    ask-question