Question
Solution
AC = Length of the direct common tangents BD = Length of direct transverse tangents Let, the distance between two circles = x cm So, BD = √[x2 - (7 + 7)2] ⇒ 48 = √(x2 - 142) ⇒ 482 = x2 - 196 [Squaring on both sides] ⇒ 2304 = x2 - 196 ⇒ x2 = 2304 + 196 = 2500 ⇒ x = √2500 = 50 cm Also, AC = √[502 - (7 - 7)2] ⇒ AC = √(2500 - 0) = √2500 = 50 cm ∴ The length of BD is 48 cm, length of AC is 50 cm
For 3x² − 10x − 8 = 0, find (1/α + 1/β).
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. 3x<...
I. 2x2 - 9 x + 9 = 0Â
II. 2y2 - 7 y + 3 = 0
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
For what values of k does the equation x² – (k+1)x + k = 0 have two distinct real roots, both greater than 1?
l. x2 - 16x + 64 = 0
II. y2Â = 64
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 3p² - 17p + 22 = 0
II. 5q² - 21q + 22 = 0
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