Question
Solution
AC = Length of the direct common tangents BD = Length of direct transverse tangents Let, the distance between two circles = x cm So, BD = β[x2 - (7 + 7)2] β 48 = β(x2 - 142) β 482 = x2 - 196Β [Squaring on both sides] β 2304 = x2 - 196 β x2 = 2304 + 196 = 2500 β x = β2500 = 50 cm Also, AC = β[502 - (7 - 7)2] β AC = β(2500 - 0) = β2500 = 50 cm β΄ The length of BD is 48 cm, length of AC is 50 cm
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